15y^2-14y+3=0

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Solution for 15y^2-14y+3=0 equation: 



15y^2-14y+3=0

a = 15; b = -14; c = +3;
Δ = b2-4ac
Δ = -142-4·15·3
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-4}{2*15}=\frac{10}{30}
=1/3
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+4}{2*15}=\frac{18}{30}
=3/5
$

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